Medium
Why is the hydrolysis of an ester slow at the beginning and fast after some time?
(N/A) The hydrolysis of an ester can be represented as follows:
$Ester + H_2O \rightarrow Acid + Alcohol$
In this reaction,the acid produced acts as an autocatalyst.
Initially,the concentration of the acid is very low,so the reaction proceeds slowly.
As the reaction progresses,the concentration of the acid increases,which accelerates the rate of the reaction.
This phenomenon,where one of the products acts as a catalyst for the reaction,is known as autocatalysis.
$Ester + H_2O \rightarrow Acid + Alcohol$
In this reaction,the acid produced acts as an autocatalyst.
Initially,the concentration of the acid is very low,so the reaction proceeds slowly.
As the reaction progresses,the concentration of the acid increases,which accelerates the rate of the reaction.
This phenomenon,where one of the products acts as a catalyst for the reaction,is known as autocatalysis.
Explore More
Similar Questions
The rate law for the reaction $A + 2B \rightarrow C + 2D$ is given by:
Easy
View SolutionThe reaction $2N_2O_5 \rightleftharpoons 2N_2O_4 + O_2$ is
Medium
View SolutionThe hypothetical reaction : $2A + B \to C + D$ is catalyzed by $E$ as indicated in the possible mechanism below -
Step-$1$ : $A + E \rightleftharpoons AE$ (fast)
Step-$2$ : $AE + A \to A_2 + E$ (slow)
Step-$3$ : $A_2 + B \to C + D$ (fast)
What rate law best agrees with this mechanism?
Step-$1$ : $A + E \rightleftharpoons AE$ (fast)
Step-$2$ : $AE + A \to A_2 + E$ (slow)
Step-$3$ : $A_2 + B \to C + D$ (fast)
What rate law best agrees with this mechanism?
Medium
View SolutionFor conversion of compound $A \rightarrow B$,the rate constant of the reaction was found to be $4.6 \times 10^{-5} \ L \ mol^{-1} \ s^{-1}$. The order of the reaction is $..........$
The mechanism of the reaction $A + 2B \to D$ is
$2B \xrightarrow{k} B_2$ $[Slow]$
$B_2 + A \to D$ $[Fast]$
The rate law expression,order with respect to $A$,order with respect to $B$ and overall order of reaction are respectively
$2B \xrightarrow{k} B_2$ $[Slow]$
$B_2 + A \to D$ $[Fast]$
The rate law expression,order with respect to $A$,order with respect to $B$ and overall order of reaction are respectively
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo