Describe the process for the extraction of chlorine.
(N/A) Chlorine is primarily extracted by the electrolysis of brine ($NaCl$ solution) in the Chlor-alkali process.
$1$. During electrolysis,$Cl^-$ ions are oxidized at the anode to form chlorine gas: $2Cl^- (aq) \rightarrow Cl_2 (g) + 2e^-$.
$2$. At the cathode,water is reduced to form hydrogen gas and hydroxide ions: $2H_2O (l) + 2e^- \rightarrow H_2 (g) + 2OH^- (aq)$.
$3$. The overall reaction is: $2NaCl (aq) + 2H_2O (l) \rightarrow Cl_2 (g) + H_2 (g) + 2NaOH (aq)$.
$1$. During electrolysis,$Cl^-$ ions are oxidized at the anode to form chlorine gas: $2Cl^- (aq) \rightarrow Cl_2 (g) + 2e^-$.
$2$. At the cathode,water is reduced to form hydrogen gas and hydroxide ions: $2H_2O (l) + 2e^- \rightarrow H_2 (g) + 2OH^- (aq)$.
$3$. The overall reaction is: $2NaCl (aq) + 2H_2O (l) \rightarrow Cl_2 (g) + H_2 (g) + 2NaOH (aq)$.
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Oxygen reacts directly with all of the following elements except:
Easy
View SolutionConsider the following reaction:
$Cl_{2(g)} + H_2O \xrightarrow{R.T.} P + Q$
If the molecular weight of $P$ is less than $Q$,then the incorrect statement is:
$Cl_{2(g)} + H_2O \xrightarrow{R.T.} P + Q$
If the molecular weight of $P$ is less than $Q$,then the incorrect statement is:
Medium
View SolutionWith reference to aqua regia,choose the correct option$(s)$.
$(1)$ Reaction of gold with aqua regia produces $NO_2$ in the absence of air.
$(2)$ Aqua regia is prepared by mixing conc. $HCl$ and conc. $HNO_3$ in $3:1$ $(v/v)$ ratio.
$(3)$ Reaction of gold with aqua regia produces an anion having $Au$ in $+3$ oxidation state.
$(4)$ The yellow colour of aqua regia is due to the presence of $NOCl$ and $Cl_2$.
$(1)$ Reaction of gold with aqua regia produces $NO_2$ in the absence of air.
$(2)$ Aqua regia is prepared by mixing conc. $HCl$ and conc. $HNO_3$ in $3:1$ $(v/v)$ ratio.
$(3)$ Reaction of gold with aqua regia produces an anion having $Au$ in $+3$ oxidation state.
$(4)$ The yellow colour of aqua regia is due to the presence of $NOCl$ and $Cl_2$.
Chlorine is liberated when we heat:
Medium
View SolutionIdentify $A, B, C$ and $D$ in the reactions:
$(I)$ $x Cl_2 + y NaOH \longrightarrow A + B + H_2 O_{(l)}$ (Cold,dil.)
$(II)$ $x Cl_2 + y NaOH \longrightarrow C + D + H_2 O_{(l)}$ (Hot,conc.)
$(I)$ $x Cl_2 + y NaOH \longrightarrow A + B + H_2 O_{(l)}$ (Cold,dil.)
$(II)$ $x Cl_2 + y NaOH \longrightarrow C + D + H_2 O_{(l)}$ (Hot,conc.)
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