Easy
Write the chemical equations for the $Van$ $Arkel$ method used for the refining of $Zr$ and $Ti$.
(N/A) The $Van$ $Arkel$ method is used for refining metals like $Zr$ and $Ti$. The process involves two main steps:
$1$. The crude metal is heated in an evacuated vessel with iodine to form a volatile metal iodide:
$Zr(s) + 2I_2(g) \rightarrow ZrI_4(g)$
$Ti(s) + 2I_2(g) \rightarrow TiI_4(g)$
$2$. The metal iodide is decomposed by heating over a tungsten filament at a higher temperature $(1800 \ K)$ to obtain pure metal:
$ZrI_4(g) \rightarrow Zr(s) + 2I_2(g)$
$TiI_4(g) \rightarrow Ti(s) + 2I_2(g)$
$1$. The crude metal is heated in an evacuated vessel with iodine to form a volatile metal iodide:
$Zr(s) + 2I_2(g) \rightarrow ZrI_4(g)$
$Ti(s) + 2I_2(g) \rightarrow TiI_4(g)$
$2$. The metal iodide is decomposed by heating over a tungsten filament at a higher temperature $(1800 \ K)$ to obtain pure metal:
$ZrI_4(g) \rightarrow Zr(s) + 2I_2(g)$
$TiI_4(g) \rightarrow Ti(s) + 2I_2(g)$
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Similar Questions
Which of the following is the correct match?
Difficult
View SolutionWhich method of purification is represented by the following equation?
$Ti_{(s)} + 2I_{2(g)}$ $\xrightarrow{523 \ K} TiI_{4(g)}$ $\xrightarrow{1700 \ K} Ti_{(s)} + 2I_{2(g)}$
$Ti_{(s)} + 2I_{2(g)}$ $\xrightarrow{523 \ K} TiI_{4(g)}$ $\xrightarrow{1700 \ K} Ti_{(s)} + 2I_{2(g)}$
Match the following items of List-$I$ with those of List-$II$:
List-$I$ List-$II$ $(A)$ Nickel $(1)$ Electrolytic refining $(B)$ Titanium $(2)$ Zone refining $(C)$ Germanium $(3)$ van-Arkel method $(D)$ Copper $(4)$ Mond process
The correct answer is:
| List-$I$ | List-$II$ |
|---|---|
| $(A)$ Nickel | $(1)$ Electrolytic refining |
| $(B)$ Titanium | $(2)$ Zone refining |
| $(C)$ Germanium | $(3)$ van-Arkel method |
| $(D)$ Copper | $(4)$ Mond process |
The correct answer is:
$Si$ and $Ge$ used for semiconductors are required to be of high purity and hence purified by:
Easy
View SolutionThe extraction of nickel involves:
Easy
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