Discuss the complex species $[Co(NH_3)_6]^{3+}$ based on Valence Bond Theory.
(N/A) $1$. The central metal ion $Co^{3+}$ has an electronic configuration of $[Ar]3d^6$.
$2$. In the presence of the strong field ligand $NH_3$,the electrons in the $3d$ orbitals pair up,leaving two $3d$ orbitals vacant.
$3$. These two $3d$ orbitals,along with one $4s$ and three $4p$ orbitals,undergo $d^2sp^3$ hybridization to form six equivalent hybrid orbitals.
$4$. Six pairs of electrons from six $NH_3$ ligands occupy these hybrid orbitals,resulting in an octahedral geometry.
$5$. Since there are no unpaired electrons,the complex is diamagnetic.
$6$. Because the inner $3d$ orbitals are involved in hybridization,it is called an inner orbital complex or a low-spin complex.
$2$. In the presence of the strong field ligand $NH_3$,the electrons in the $3d$ orbitals pair up,leaving two $3d$ orbitals vacant.
$3$. These two $3d$ orbitals,along with one $4s$ and three $4p$ orbitals,undergo $d^2sp^3$ hybridization to form six equivalent hybrid orbitals.
$4$. Six pairs of electrons from six $NH_3$ ligands occupy these hybrid orbitals,resulting in an octahedral geometry.
$5$. Since there are no unpaired electrons,the complex is diamagnetic.
$6$. Because the inner $3d$ orbitals are involved in hybridization,it is called an inner orbital complex or a low-spin complex.
Explore More
Similar Questions
Match List-$I$ (Species) with List-$II$ (Hybrid orbitals used by the central atom in their formation) and select the correct answer.
List-$I$ List-$II$ $A. \, Ni(CN)_5^{3-}$ $1. \, sp^3$ $B. \, CuCl_5^{3-}$ $2. \, dsp^2$ $C. \, AuCl_4^-$ $3. \, sp^3d_{z^2}$ $D. \, ClO_4^-$ $4. \, d_{x^2-y^2}sp^3$
| List-$I$ | List-$II$ |
| $A. \, Ni(CN)_5^{3-}$ | $1. \, sp^3$ |
| $B. \, CuCl_5^{3-}$ | $2. \, dsp^2$ |
| $C. \, AuCl_4^-$ | $3. \, sp^3d_{z^2}$ |
| $D. \, ClO_4^-$ | $4. \, d_{x^2-y^2}sp^3$ |
Difficult
View SolutionExplain Valence Bond Theory.
Medium
View SolutionMatch the type of hybridization given in List-$I$ with the molecules/ions given in List-$II$.
List-$I$ List-$II$ $(1)$ $dsp^2$ $(A)$ $BrF_5$ $(2)$ $sp^3d^2$ $(B)$ $[Co(NH_3)_6]^{3+}$ $(3)$ $sp^3d$ $(C)$ $[PtCl_4]^{2-}$ $(4)$ $d^2sp^3$ $(D)$ $PCl_5$
| List-$I$ | List-$II$ |
| $(1)$ $dsp^2$ | $(A)$ $BrF_5$ |
| $(2)$ $sp^3d^2$ | $(B)$ $[Co(NH_3)_6]^{3+}$ |
| $(3)$ $sp^3d$ | $(C)$ $[PtCl_4]^{2-}$ |
| $(4)$ $d^2sp^3$ | $(D)$ $PCl_5$ |
Medium
View SolutionIf an iron $(III)$ complex with the formula $[Fe(NH_3)_{x}(CN)_{y}]^{-}$ has no electron in its $e_g$ orbital, then the value of $x+y$ is
The geometry of $Ni(CO)_4$ and $[Ni(PPh_3)_2Cl_2]$ are
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo