(A) The dimensional formula of density $\rho$ is $[M L^{-3}]$.The dimensional formula of acceleration $g$ is $[L T^{-2}]$.The dimensional formula of v

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(A) The dimensional formula of density $\rho$ is $[M L^{-3}]$.The dimensional formula of acceleration $g$ is $[L T^{-2}]$.The dimensional formula of velocity $v$ is $[L T^{-1}]$.Now,the dimensional formula of the product $\rho g v$ is given by:$[\rho g v] = [\rho] [g] [v]$$[\rho g v] = [M L^{-3}] [L T^{-2}] [L T^{-1}]$$[\rho g v] = [M L^{-3+1+1} T^{-2-1}]$$[\rho g v] = [M L^{-1} T^{-3}]$

Class 11 Physics Units, Dimensions and Measurement Dimensions and Dimensional Formula

Medium

Find the dimensional formula of $\rho g v$,where $\rho = \text{density}$,$g = \text{acceleration}$,and $v = \text{velocity}$.

A
$[M L^{-1} T^{-3}]$
B
$[M L^{-2} T^{-2}]$
C
$[M L^{-3} T^{-1}]$
D
$[M L^{-1} T^{-2}]$

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Dimensions and Dimensional Formula

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Find the dimensional formula of $\rho g v$,where $\rho = \text{density}$,$g = \text{acceleration}$,and $v = \text{velocity}$.

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