(A) The bromine $(Br_2)$ acts as an oxidizing agent and displaces iodine $(I_2)$ from the potassium iodide $(KI)$ present in the starch iodide paper.$

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(A) The bromine $(Br_2)$ acts as an oxidizing agent and displaces iodine $(I_2)$ from the potassium iodide $(KI)$ present in the starch iodide paper.$Br_2 + 2KI \rightarrow 2KBr + I_2$The liberated iodine $(I_2)$ then reacts with the starch to form a blue-black complex,which is commonly referred to as a blue color.