(B) The resultant $R$ of two vectors $\vec{A}$ and $\vec{B}$ is given by $R = \sqrt{A^2 + B^2 + 2AB \cos \theta}$,where $\theta$ is the angle between

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(B) The resultant $R$ of two vectors $\vec{A}$ and $\vec{B}$ is given by $R = \sqrt{A^2 + B^2 + 2AB \cos \theta}$,where $\theta$ is the angle between them.For the resultant to be maximum,$\cos \theta$ must be maximum,i.e.,$\cos \theta = 1$,which implies $\theta = 0^o$. Thus,$(1-c)$.For the resultant to be minimum,$\cos \theta$ must be minimum,i.e.,$\cos \theta = -1$,which implies $\theta = 180^o$. Thus,$(2-a)$.Therefore,the correct matching is $(1-c), (2-a)$.

Class 11 Physics 3-1.Vectors Addition and Subtraction of Vectors

Easy

Match Column-$I$ with Column-$II$.

Column-$I$ Column-$II$

$(1)$ Resultant of two vectors is maximum $(a)$ $180^o$

$(2)$ Resultant of two vectors is minimum $(b)$ $90^o$

$(c)$ $0^o$

Column-$I$	Column-$II$
$(1)$ Resultant of two vectors is maximum	$(a)$ $180^o$
$(2)$ Resultant of two vectors is minimum	$(b)$ $90^o$
	$(c)$ $0^o$

A
$(1-c), (2-b)$
B
$(1-c), (2-a)$
C
$(1-b), (2-a)$
D
$(1-a), (2-c)$

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3-1.Vectors

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Addition and Subtraction of Vectors

Two vectors $\vec A$ and $\vec B$ have magnitudes $2$ and $1$ respectively. If the angle between $\vec A$ and $\vec B$ is $60^{\circ}$,then which of the following vectors may be equal to $\frac{\vec A}{2} - \vec B$?

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The vectors $\vec{A}$ and $\vec{B}$ are such that $|\vec{A}+\vec{B}|=|\vec{A}-\vec{B}|$. The angle between the two vectors is: (in $^{\circ}$)

DifficultAIPMT 1996

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The vectors $(\vec{A} + \vec{B})$ and $(\vec{A} - \vec{B})$ are perpendicular to each other. This is possible under the condition:

MediumMHT CET 2026

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The angle $\beta$ between vector $\overrightarrow{A}$ and the resultant vector $(\overrightarrow{A}-\overrightarrow{B})$ is given by:

DifficultJEE MAIN 2021

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Let the two forces have equal magnitude $A$. If the magnitude of the resultant is $\frac{2A}{3}$,then the angle between those two forces is:

EasyMHT CET 2020

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Match Column-$I$ with Column-$II$. Column-$I$ Column-$II$ $(1)$ Resultant of two vectors is maximum $(a)$ $180^o$ $(2)$ Resultant of two vectors is minimum $(b)$ $90^o$ $(c)$ $0^o$

Similar Questions

Two vectors $\vec A$ and $\vec B$ have magnitudes $2$ and $1$ respectively. If the angle between $\vec A$ and $\vec B$ is $60^{\circ}$,then which of the following vectors may be equal to $\frac{\vec A}{2} - \vec B$?

The vectors $\vec{A}$ and $\vec{B}$ are such that $|\vec{A}+\vec{B}|=|\vec{A}-\vec{B}|$. The angle between the two vectors is: (in $^{\circ}$)

The vectors $(\vec{A} + \vec{B})$ and $(\vec{A} - \vec{B})$ are perpendicular to each other. This is possible under the condition:

The angle $\beta$ between vector $\overrightarrow{A}$ and the resultant vector $(\overrightarrow{A}-\overrightarrow{B})$ is given by:

Let the two forces have equal magnitude $A$. If the magnitude of the resultant is $\frac{2A}{3}$,then the angle between those two forces is:

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Match Column-$I$ with Column-$II$.

Column-$I$ Column-$II$

$(1)$ Resultant of two vectors is maximum $(a)$ $180^o$

$(2)$ Resultant of two vectors is minimum $(b)$ $90^o$

$(c)$ $0^o$