Match the items in Column-I with Column-II. | vedclass

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(C) The work done by a force is given by $W = \vec{F} \cdot \vec{d} = Fd \cos 	heta$,where $	heta$ is the angle between the force and displacement.$

Vedclass · Accepted Answer

$1-c, 2-a, 3-b$

Vedclass · Answer

(C) The work done by a force is given by $W = \vec{F} \cdot \vec{d} = Fd \cos 	heta$,where $	heta$ is the angle between the force and displacement.$(1)$ Work done by centripetal force is zero because the force is always perpendicular to the displacement ($	heta = 90^\circ$,$\cos 90^\circ = 0$). Thus,$(1-c)$.$(2)$ Work done by gravitational force is positive when the body moves in the direction of the force (downward motion,$	heta = 0^\circ$,$\cos 0^\circ = 1$). Thus,$(2-a)$.$(3)$ Work done against gravitational force is negative when the body moves upward (displacement is opposite to the force,$	heta = 180^\circ$,$\cos 180^\circ = -1$). Thus,$(3-b)$.Therefore,the correct matching is $(1-c, 2-a, 3-b)$.

Column-$I$	Column-$II$
$(1)$ Work done is zero	$(a)$ By gravitational force (when body moves down)
$(2)$ Work done is positive	$(b)$ Against gravitational force (when body moves up)
$(3)$ Work done is negative	$(c)$ By centripetal force

Match the items in Column-$I$ with Column-$II$.

Column-$I$ Column-$II$

$(1)$ Work done is zero $(a)$ By gravitational force (when body moves down)

$(2)$ Work done is positive $(b)$ Against gravitational force (when body moves up)

$(3)$ Work done is negative $(c)$ By centripetal force

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Match the items in Column-$I$ with Column-$II$. Column-$I$ Column-$II$ $(1)$ Work done is zero $(a)$ By gravitational force (when body moves down) $(2)$ Work done is positive $(b)$ Against gravitational force (when body moves up) $(3)$ Work done is negative $(c)$ By centripetal force