Calculate the mass of oxygen present in 0.1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The chemical formula is $Na_2CO_3 \cdot 10H_2O$.In $1 \ mol$ of $Na_2CO_3 \cdot 10H_2O$,there are $3$ oxygen atoms in $Na_2CO_3$ and $10$ oxygen a

Vedclass · Accepted Answer

$20.8$

Vedclass · Answer

(A) The chemical formula is $Na_2CO_3 \cdot 10H_2O$.In $1 \ mol$ of $Na_2CO_3 \cdot 10H_2O$,there are $3$ oxygen atoms in $Na_2CO_3$ and $10$ oxygen atoms in $10H_2O$,totaling $13$ moles of oxygen atoms.For $0.1 \ mol$ of the compound,the moles of oxygen atoms = $0.1 	imes 13 = 1.3 \ mol$.The molar mass of oxygen is $16 \ g/mol$.Mass of oxygen = $1.3 \ mol 	imes 16 \ g/mol = 20.8 \ g$.

Calculate the mass of oxygen present in $0.1 \ mol$ of $Na_2CO_3 \cdot 10H_2O$. (in $g$)

Similar Questions

How many atoms are contained in $5.6 \ L$ of oxygen gas at $STP$?

The atomic weights of two elements $A$ and $B$ are $40$ and $80$ respectively. If $x \ g$ of $A$ contains $y$ atoms,how many atoms are present in $2x \ g$ of $B$?

What quantity of $H_2O$ in grams is present in $0.25 \text{ mol}$ of it (in $\text{ g}$)?

The mass of one hydrogen atom is of the order of

$A$ mixture has $18 \ g$ of water and $414 \ g$ of ethanol. The mole fraction of water in the mixture is (assume ideal behavior of the mixture):

Vedclass Test Series

Exam Paper Generator

Online Exam Module