What is the radius of the stationary orbits $(n)$? State the formula.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The radius of the stationary orbits is given by the formula: $r_{n} = \frac{n^{2} a_{0}}{Z} = \frac{(52.9) n^{2}}{Z} \, pm$ (for a $1$-electron system).
Where:
$n = \text{principal quantum number} = \text{orbit number} = \text{energy level} = 1, 2, 3, \dots$
$Z = \text{atomic number}$
$a_{0} = 52.9 \, pm = 0.0529 \, nm = 5.29 \times 10^{-11} \, m$ (Bohr radius).

Explore More

Similar Questions

Which one of the following is incorrect for the Bohr model of the hydrogen atom?

The Ritz combination principle states that:

Number of waves made by Bohr's electron in one complete revolution in the $3^{rd}$ orbit.

If the electron of a hydrogen atom is present in the first orbit, the total energy of the electron is

What is the number of waves formed by an electron in the $5^{th}$ Bohr orbit of a hydrogen atom?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo