Write the electronic configuration of an atom | vedclass

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Question

(B) The atomic number $Z = 16$ corresponds to Sulfur $(S)$.The electronic configuration is: $1s^2 2s^2 2p^6 3s^2 3p^4$.Total $p$ electrons: $2p^6 + 3p

Vedclass · Accepted Answer

$10$ $p$ electrons,$7$ fully filled,$2$ half-filled

Vedclass · Answer

(B) The atomic number $Z = 16$ corresponds to Sulfur $(S)$.The electronic configuration is: $1s^2 2s^2 2p^6 3s^2 3p^4$.Total $p$ electrons: $2p^6 + 3p^4 = 10$ electrons.Orbital distribution:$1s$: $2$ electrons (fully filled)$2s$: $2$ electrons (fully filled)$2p$: $6$ electrons (three $2p$ orbitals fully filled)$3s$: $2$ electrons (fully filled)$3p$: $4$ electrons ($3p_x^2, 3p_y^1, 3p_z^1$ - one orbital fully filled,two half-filled).Total fully filled orbitals: $1s, 2s, 2p_x, 2p_y, 2p_z, 3s, 3p_x = 7$.Total half-filled orbitals: $3p_y, 3p_z = 2$.

Write the electronic configuration of an atom with $Z = 16$. How many $p$ electrons are present in it,and how many fully filled and half-filled orbitals does it contain?

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