Which of the following orbitals are possible: | vedclass

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(B) For an orbital to be possible,the principal quantum number $n$ and the azimuthal quantum number $l$ must satisfy the condition $l < n$.For $1p$: $

Vedclass · Accepted Answer

$2s, 2p$

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(B) For an orbital to be possible,the principal quantum number $n$ and the azimuthal quantum number $l$ must satisfy the condition $l For $1p$: $n=1, l=1$. Since $l$ is not less than $n$,$1p$ is not possible.For $2s$: $n=2, l=0$. Since $l For $2p$: $n=2, l=1$. Since $l For $3f$: $n=3, l=3$. Since $l$ is not less than $n$,$3f$ is not possible.Therefore,$2s$ and $2p$ are the possible orbitals.

Which of the following orbitals are possible: $1p, 2s, 2p, 3f$?

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