Match the species in List-$I$ with their correct electronic configuration in List-$II$.
List-$I$ List-$II$ $(1) \ \text{Cr}$ $(A) \ [\text{Ar}] \ 3d^8 4s^0$ $(2) \ \text{Fe}^{2+}$ $(B) \ [\text{Ar}] \ 3d^{10} 4s^1$ $(3) \ \text{Ni}^{2+}$ $(C) \ [\text{Ar}] \ 3d^6 4s^0$ $(4) \ \text{Cu}$ $(D) \ [\text{Ar}] \ 3d^5 4s^1$ $(E) \ [\text{Ar}] \ 3d^6 4s^2$
| List-$I$ | List-$II$ |
| $(1) \ \text{Cr}$ | $(A) \ [\text{Ar}] \ 3d^8 4s^0$ |
| $(2) \ \text{Fe}^{2+}$ | $(B) \ [\text{Ar}] \ 3d^{10} 4s^1$ |
| $(3) \ \text{Ni}^{2+}$ | $(C) \ [\text{Ar}] \ 3d^6 4s^0$ |
| $(4) \ \text{Cu}$ | $(D) \ [\text{Ar}] \ 3d^5 4s^1$ |
| $(E) \ [\text{Ar}] \ 3d^6 4s^2$ |
(D) The correct matching is: $(1-D, 2-C, 3-A, 4-B)$.
$(1) \ \text{Cr} \ (Z=24): [\text{Ar}] \ 3d^5 4s^1$ (Matches $D$)
$(2) \ \text{Fe}^{2+} \ (Z=26): [\text{Ar}] \ 3d^6 4s^0$ (Matches $C$)
$(3) \ \text{Ni}^{2+} \ (Z=28): [\text{Ar}] \ 3d^8 4s^0$ (Matches $A$)
$(4) \ \text{Cu} \ (Z=29): [\text{Ar}] \ 3d^{10} 4s^1$ (Matches $B$)
$(1) \ \text{Cr} \ (Z=24): [\text{Ar}] \ 3d^5 4s^1$ (Matches $D$)
$(2) \ \text{Fe}^{2+} \ (Z=26): [\text{Ar}] \ 3d^6 4s^0$ (Matches $C$)
$(3) \ \text{Ni}^{2+} \ (Z=28): [\text{Ar}] \ 3d^8 4s^0$ (Matches $A$)
$(4) \ \text{Cu} \ (Z=29): [\text{Ar}] \ 3d^{10} 4s^1$ (Matches $B$)
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