If the period is $6$,then $n = 6$ and $l = 0, 1, 2, 3, 4$. Why is the number of elements in this period still $32$?

(N/A) For $n = 6$,the subshells available are $6s, 6p, 5d, 4f$. The $5g$ and $6g$ subshells are not filled in the ground state of known elements because their energy is significantly higher than the $7s$ orbital.

$n=6$ subshells	$6s, 6p, 5d, 4f$
Number of orbitals	$1 (6s) + 3 (6p) + 5 (5d) + 7 (4f) = 16$ orbitals
Total elements	$16 \times 2 = 32$ elements