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(A) The electronic configuration of Beryllium ($Be$,$Z=4$) is $1s^{2} 2s^{2}$. The first ionization enthalpy involves the removal of an electron from

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$2s$ and $2p$

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(A) The electronic configuration of Beryllium ($Be$,$Z=4$) is $1s^{2} 2s^{2}$. The first ionization enthalpy involves the removal of an electron from the $2s$ orbital.The electronic configuration of Boron ($B$,$Z=5$) is $1s^{2} 2s^{2} 2p^{1}$. The first ionization enthalpy involves the removal of an electron from the $2p$ orbital.Therefore,the electrons are removed from $2s$ and $2p$ respectively.

Which electrons are removed to determine the ionization enthalpy of beryllium and boron,respectively?

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