What will be the position in the periodic tab | vedclass

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(A) Given the electronic configuration $ns^2 np^4$ with $n = 3$,the configuration is $3s^2 3p^4$. Since the principal quantum number $n = 3$,the eleme

Vedclass · Accepted Answer

Period $3$,Group $16$

Vedclass · Answer

(A) Given the electronic configuration $ns^2 np^4$ with $n = 3$,the configuration is $3s^2 3p^4$. Since the principal quantum number $n = 3$,the element belongs to the $3^{rd}$ period. The number of valence electrons is $2 + 4 = 6$. For $p$-block elements,the group number is calculated as $10 + 	ext{valence electrons} = 10 + 6 = 16$. Thus,the element is in period $3$ and group $16$.

What will be the position in the periodic table for an element with the electronic configuration $ns^2 np^4$ where $n = 3$?

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