Compare the polarity of the N-H bond and the | vedclass

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(B) The polarity of a covalent bond depends on the electronegativity difference between the bonded atoms. Electronegativity values are: $N = 3.04$,$H

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The $N-F$ bond is more polar than the $N-H$ bond.

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(B) The polarity of a covalent bond depends on the electronegativity difference between the bonded atoms. Electronegativity values are: $N = 3.04$,$H = 2.20$,and $F = 3.98$. The electronegativity difference for the $N-H$ bond is $|3.04 - 2.20| = 0.84$. The electronegativity difference for the $N-F$ bond is $|3.04 - 3.98| = 0.94$. Since $0.94 > 0.84$,the $N-F$ bond has a larger electronegativity difference and is therefore more polar than the $N-H$ bond.

Compare the polarity of the $N-H$ bond and the $N-F$ bond.

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