Which orbital is more electronegative among $sp$,$sp^2$,and $sp^3$? Why?

The shape of a molecule depends on which factor?

In which of the following molecules is the $N$ atom not $sp^2$ hybridized?

Which is the correct statement?
As the $s$-character of a hybrid orbital decreases:
$(I)$ The bond angle decreases
$(II)$ The bond strength increases
$(III)$ The bond length increases
$(IV)$ Size of orbitals increases

The hybridization of orbitals of $N$ atom in $NO_{3}^{-}$,$NO_{2}^{+}$ and $NH_{4}^{+}$ are respectively $:$

The trigonal bipyramidal geometry results from the hybridization: