Match the compounds given in List-$I$ with their dipole moments given in List-$II$.
List-$I$List-$II$
$(1)$ ${\rm{HBr}}$$(A)$ $0.23$
$(2)$ ${{\rm{H}}_2}{\rm{S}}$$(B)$ $1.04$
$(3)$ ${\rm{N}}{{\rm{F}}_3}$$(C)$ $1.07$
$(4)$ ${\rm{CC}}{{\rm{l}}_4}$$(D)$ $0.79$
$(5)$ ${\rm{CHC}}{{\rm{l}}_3}$$(E)$ $0.00$
$(F)$ $0.95$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The dipole moments ($\mu$ in $D$) for the given compounds are as follows:
$(1)$ ${\rm{HBr}}$: $0.79 \ D$ $(1-D)$
$(2)$ ${{\rm{H}}_2}{\rm{S}}$: $0.95 \ D$ $(2-F)$
$(3)$ ${\rm{N}}{{\rm{F}}_3}$: $0.23 \ D$ $(3-A)$
$(4)$ ${\rm{CC}}{{\rm{l}}_4}$: $0.00 \ D$ $(4-E)$
$(5)$ ${\rm{CHC}}{{\rm{l}}_3}$: $1.04 \ D$ $(5-B)$
Therefore, the correct matching is $(1-D, 2-F, 3-A, 4-E, 5-B)$.

Explore More

Similar Questions

Carbon tetrachloride has no net dipole moment because of

Among $H_2S$, $H_2O$, $NF_3$, $NH_3$ and $CHCl_3$, identify the molecule $(X)$ with the lowest dipole moment value. The number of lone pairs of electrons present on the central atom of the molecule $(X)$ is:

The molecule with non-zero dipole moment is

Explain the dipole moment of a triatomic molecule $(AB_2)$.

Difficult
View Solution

The compound of xenon with zero dipole moment is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo