Arrange the following forces in the increasin | vedclass

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(A) The interaction energies of the given forces are as follows:$1$. London forces (Dispersion forces): $1$ to $10 \ kJ \ mol^{-1}$$2$. Dipole-dipole

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London forces < Dipole-dipole forces < Hydrogen bond < Covalent bond

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(A) The interaction energies of the given forces are as follows:$1$. London forces (Dispersion forces): $1$ to $10 \ kJ \ mol^{-1}$$2$. Dipole-dipole forces: $1$ to $3 \ kcal \ mol^{-1}$ (approx. $4$ to $12 \ kJ \ mol^{-1}$)$3$. Hydrogen bond: $10$ to $40 \ kJ \ mol^{-1}$$4$. Covalent bond: $50$ to $100 \ kcal \ mol^{-1}$ (approx. $200$ to $400 \ kJ \ mol^{-1}$)Comparing these values,the increasing order of interaction energy is:$London \ forces < Dipole-dipole \ forces < Hydrogen \ bond < Covalent \ bond$

Arrange the following forces in the increasing order of their interaction energy:
London forces,Covalent bond,Hydrogen bond,Dipole-dipole forces

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Arrange the following forces in the increasing order of their interaction energy:London forces,Covalent bond,Hydrogen bond,Dipole-dipole forces