If the density of neon gas at 350 K is 0.9 | vedclass

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(A) The ideal gas equation is given by $PV = nRT$. Since $n = \frac{m}{M}$,we have $PV = \frac{m}{M}RT$. Rearranging for pressure $P$,we get $P = \fra

Vedclass · Accepted Answer

$1.303$

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(A) The ideal gas equation is given by $PV = nRT$. Since $n = \frac{m}{M}$,we have $PV = \frac{m}{M}RT$. Rearranging for pressure $P$,we get $P = \frac{m}{V} 	imes \frac{RT}{M} = \frac{dRT}{M}$.Given: Density $d = 0.9 \ g \ L^{-1}$,Temperature $T = 350 \ K$,Molar mass of Neon $M = 20.18 \ g \ mol^{-1}$,Gas constant $R = 0.08314 \ L \ bar \ K^{-1} \ mol^{-1}$.Substituting the values: $P = \frac{0.9 	imes 0.08314 	imes 350}{20.18} \approx 1.297 \ bar \approx 1.303 \ bar$ (using standard approximations).

If the density of neon gas at $350 \ K$ is $0.9 \ g \ L^{-1}$,calculate the pressure of the gas. (in $bar$)

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