The solubility product of $AgI$ at $25^{\circ} C$ is $1.0 \times 10^{-16} \ mol^2 \ L^{-2}$. What is the solubility of $AgI$ in $10^{-4} \ N \ KI$ at $25^{\circ} C$?
- A$1.0 \times 10^{-12} \ mol \ L^{-1}$
- B$1.0 \times 10^{-16} \ mol \ L^{-1}$
- C$1.0 \times 10^{-8} \ mol \ L^{-1}$
- D$2.0 \times 10^{-16} \ mol \ L^{-1}$
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Similar Questions
The solubility of $CaF_2$ is $2 \times 10^{-4} \, mol/L$. Its solubility product $(K_{sp})$ is:
MediumAIPMT 1999
View SolutionThe correct order of solubility of the given salts in water at $298 K$ is:
Salt $K_{sp}$ at $298 K$ $AgBr$ $5.0 \times 10^{-13}$ $Zn(OH)_2$ $1.0 \times 10^{-15}$ $Hg_2Cl_2$ $1.3 \times 10^{-18}$
| Salt | $K_{sp}$ at $298 K$ |
| $AgBr$ | $5.0 \times 10^{-13}$ |
| $Zn(OH)_2$ | $1.0 \times 10^{-15}$ |
| $Hg_2Cl_2$ | $1.3 \times 10^{-18}$ |
DifficultNEET 2026
View SolutionDerive the solubility product $(K_{sp})$ expression for the following sparingly soluble salts:
$(i)$ Two ions having $MX$ formula
$(ii)$ Three ions having $MX_{2}$ or $M_{2}X$ types
$(iii)$ Four ions having $AX_{3}$ or $A_{3}X$ type salts
$(iv)$ Five ions $A_{2}X_{3}$ or $A_{3}X_{2}$ type salts.
$(i)$ Two ions having $MX$ formula
$(ii)$ Three ions having $MX_{2}$ or $M_{2}X$ types
$(iii)$ Four ions having $AX_{3}$ or $A_{3}X$ type salts
$(iv)$ Five ions $A_{2}X_{3}$ or $A_{3}X_{2}$ type salts.
Easy
View SolutionThe conductivity of a saturated solution of $BaSO_4$ is $3.06 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$ and its equivalent conductance is $1.53 \ \Omega^{-1} \ cm^{2} \ equivalent^{-1}$. The $K_{sp}$ of the $BaSO_4$ will be
Medium
View SolutionPrecipitation of $CaF_2$ $(K_{sp} = 1.7 \times 10^{-10})$ occurs when equal volumes of which of the following are mixed?
Difficult
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