0.1 , mol , L^{-1} means how much mol , m^{-3 | vedclass

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Question

(A) Given concentration is $0.1 \, mol \, L^{-1}$.We know that $1 \, L = 10^{-3} \, m^3$ and $1 \, L = 1000 \, cm^3$.To convert $mol \, L^{-1}$ to $mo

Vedclass · Accepted Answer

$100 \, mol \, m^{-3}$ and $10^{-4} \, mol \, cm^{-3}$

Vedclass · Answer

(A) Given concentration is $0.1 \, mol \, L^{-1}$.We know that $1 \, L = 10^{-3} \, m^3$ and $1 \, L = 1000 \, cm^3$.To convert $mol \, L^{-1}$ to $mol \, m^{-3}$:$0.1 \, mol \, L^{-1} = \frac{0.1 \, mol}{10^{-3} \, m^3} = 0.1 	imes 10^3 \, mol \, m^{-3} = 100 \, mol \, m^{-3}$.To convert $mol \, L^{-1}$ to $mol \, cm^{-3}$:$0.1 \, mol \, L^{-1} = \frac{0.1 \, mol}{1000 \, cm^3} = 0.1 	imes 10^{-3} \, mol \, cm^{-3} = 10^{-4} \, mol \, cm^{-3}$.Thus,the correct values are $100 \, mol \, m^{-3}$ and $10^{-4} \, mol \, cm^{-3}$.

List-$A$	List-$B$
$(1)$ Electric current	$(A)$ Kilogram
$(2)$ Luminous intensity	$(B)$ Mole
$(3)$ Amount of substance	$(C)$ Ampere
$(4)$ Mass	$(D)$ Candela

$0.1 \, mol \, L^{-1}$ means how much $mol \, m^{-3}$ and how much $mol \, cm^{-3}$?

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