$0.1914 \ g$ of an organic acid is dissolved in approx. $20 \ mL$ of water. $25 \ mL$ of $0.12 \ N$ $NaOH$ is required for the complete neutralization of the acid solution. The equivalent weight of the acid is
- A$65$
- B$64$
- C$63.8$
- D$62.5$
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