40 % of 1640 + ? = 35 % of 980 + 150 % of 850 | vedclass

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(C) Given equation: $40 \%$ of $1640 + ? = 35 \%$ of $980 + 150 \%$ of $850$Let the missing value be $x$.$x = (35 \% 	ext{ of } 980) + (150 \% 	ext{

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$962$

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(C) Given equation: $40 \%$ of $1640 + ? = 35 \%$ of $980 + 150 \%$ of $850$Let the missing value be $x$.$x = (35 \% 	ext{ of } 980) + (150 \% 	ext{ of } 850) - (40 \% 	ext{ of } 1640)$Calculate each term:$35 \% 	ext{ of } 980 = \frac{35}{100} 	imes 980 = 343$$150 \% 	ext{ of } 850 = \frac{150}{100} 	imes 850 = 1275$$40 \% 	ext{ of } 1640 = \frac{40}{100} 	imes 1640 = 656$Substitute the values:$x = 343 + 1275 - 656$$x = 1618 - 656$$x = 962$

$40 \%$ of $1640 + ? = 35 \%$ of $980 + 150 \%$ of $850$

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