(A) 's one day's work $= \frac{1}{4}$$B$'s one day's work $= \frac{1}{6}$Combined one day's work of $A$ and $B = \frac{1}{4} + \frac{1}{6} = \frac{3+2

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(A) 's one day's work $= \frac{1}{4}$$B$'s one day's work $= \frac{1}{6}$Combined one day's work of $A$ and $B = \frac{1}{4} + \frac{1}{6} = \frac{3+2}{12} = \frac{5}{12}$Total days required to complete the work together $= \frac{1}{5/12} = \frac{12}{5} = 2 \frac{2}{5} \text{ days}$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

$A$ completes a piece of work in $4 \text{ days}$ and $B$ completes it in $6 \text{ days}$. If they both work on it together,then the number of days required to complete the same work is (in $\text{days}$):

A
$2 \frac{2}{5}$
B
$3 \frac{2}{5}$
C
$3 \frac{5}{2}$
D
$2 \frac{5}{2}$

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Time and Work and Wages

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Time and Work

If $5$ men and $3$ boys can reap $23 \text{ hectares}$ in $4 \text{ days}$ and if $3$ men and $2$ boys can reap $7 \text{ hectares}$ in $2 \text{ days}$,how many boys must assist $7$ men in order that they may reap $45 \text{ hectares}$ in $6 \text{ days}$?

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$A$ takes twice as much time as $B$ or thrice as much time as $C$ to finish a piece of work. Working together,they can finish the work in $2$ days. $B$ can do the work alone in (in days):

Medium

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If a work can be completed by $A$ in $30 \text{ days}$ and by $B$ in $60 \text{ days}$,then the number of days taken by them to finish the work,working together,is

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$A$ can do a piece of work in $8$ days. $A$ undertook it for $Rs. 320$. With the help of $B$,he finishes the work in $6$ days. $B$'s share is (in $Rs.$):

Medium

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$A$ is thrice as good a workman as $B$,therefore,$A$ is able to finish a piece of work in $60 \, days$ less than $B$. The time (in $days$) in which they can do it working together is

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$A$ completes a piece of work in $4 \text{ days}$ and $B$ completes it in $6 \text{ days}$. If they both work on it together,then the number of days required to complete the same work is (in $\text{days}$):

Similar Questions

If $5$ men and $3$ boys can reap $23 \text{ hectares}$ in $4 \text{ days}$ and if $3$ men and $2$ boys can reap $7 \text{ hectares}$ in $2 \text{ days}$,how many boys must assist $7$ men in order that they may reap $45 \text{ hectares}$ in $6 \text{ days}$?

$A$ takes twice as much time as $B$ or thrice as much time as $C$ to finish a piece of work. Working together,they can finish the work in $2$ days. $B$ can do the work alone in (in days):

If a work can be completed by $A$ in $30 \text{ days}$ and by $B$ in $60 \text{ days}$,then the number of days taken by them to finish the work,working together,is

$A$ can do a piece of work in $8$ days. $A$ undertook it for $Rs. 320$. With the help of $B$,he finishes the work in $6$ days. $B$'s share is (in $Rs.$):

$A$ is thrice as good a workman as $B$,therefore,$A$ is able to finish a piece of work in $60 \, days$ less than $B$. The time (in $days$) in which they can do it working together is

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