(B) Let the total work be $1$ unit.Rate of $(A+B+C) = \frac{1}{30}$ work per $min$.Rate of $(A+B) = \frac{1}{50}$ work per $min$.Rate of $C = \text{Ra

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(B) Let the total work be $1$ unit.Rate of $(A+B+C) = \frac{1}{30}$ work per $min$.Rate of $(A+B) = \frac{1}{50}$ work per $min$.Rate of $C = \text{Rate of } (A+B+C) - \text{Rate of } (A+B) = \frac{1}{30} - \frac{1}{50}$.Taking $LCM$ of $30$ and $50$ as $150$,we get:Rate of $C = \frac{5-3}{150} = \frac{2}{150} = \frac{1}{75}$ work per $min$.Therefore,$C$ alone can complete the work in $75\, min$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

$A, B$ and $C$ together can complete a piece of work in $30\, min$. $A$ and $B$ together can complete the same work in $50\, min$. $C$ alone can complete the work in? (in $min$)

A
$60$
B
$75$
C
$80$
D
$150$

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Time and Work and Wages

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Time and Work

$4$ men and $6$ women complete a work in $8$ days,$2$ men and $9$ women also complete the same work in $8$ days. In how many days will $18$ women complete the work?

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$A$ can do a job in $6 \, days$ and $A$ and $B$ can do it together in $2 \, days.$ How many $days$ will be taken by $B$ to do the job alone?

Medium

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$40$ men can complete a work in $40$ days. They started the work together. But at the end of each $10^{th}$ day,$5$ men left the job. The work would have been completed in (in days):

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$A$ is thrice as good a workman as $B$ and therefore is able to finish a job in $60\, days$ less than $B.$ Working together,they can do it in (in $days$)

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$A$'s $2$ days work is equal to $B$'s $3$ days work. If $A$ can complete the work in $8$ days,then to complete the work $B$ will take (in days):

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$A, B$ and $C$ together can complete a piece of work in $30\, min$. $A$ and $B$ together can complete the same work in $50\, min$. $C$ alone can complete the work in? (in $min$)

Similar Questions

$4$ men and $6$ women complete a work in $8$ days,$2$ men and $9$ women also complete the same work in $8$ days. In how many days will $18$ women complete the work?

$A$ can do a job in $6 \, days$ and $A$ and $B$ can do it together in $2 \, days.$ How many $days$ will be taken by $B$ to do the job alone?

$40$ men can complete a work in $40$ days. They started the work together. But at the end of each $10^{th}$ day,$5$ men left the job. The work would have been completed in (in days):

$A$ is thrice as good a workman as $B$ and therefore is able to finish a job in $60\, days$ less than $B.$ Working together,they can do it in (in $days$)

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