A and B can complete a piece of work in 30 te | vedclass

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(C) Let the work done by $(A+B)$ in $1 	ext{ day} = \frac{1}{30}$.Let the work done by $(B+C)$ in $1 	ext{ day} = \frac{1}{40}$.Let the work done by

Vedclass · Accepted Answer

$26 \frac{2}{3}$

Vedclass · Answer

(C) Let the work done by $(A+B)$ in $1 	ext{ day} = \frac{1}{30}$.Let the work done by $(B+C)$ in $1 	ext{ day} = \frac{1}{40}$.Let the work done by $(C+A)$ in $1 	ext{ day} = \frac{1}{60}$.Adding these,we get $2(A+B+C)$'s $1 	ext{ day}$ work:$2(A+B+C) = \frac{1}{30} + \frac{1}{40} + \frac{1}{60} = \frac{4+3+2}{120} = \frac{9}{120} = \frac{3}{40}$.Therefore,$(A+B+C)$'s $1 	ext{ day}$ work $= \frac{3}{40} 	imes \frac{1}{2} = \frac{3}{80}$.Thus,$A, B, C$ together can complete the work in $\frac{80}{3} = 26 \frac{2}{3} 	ext{ days}$.

$A$ and $B$ can complete a piece of work in $30 \text{ days}$,$B$ and $C$ in $40 \text{ days}$,while $C$ and $A$ in $60 \text{ days}$. $A, B, C$ together can complete the work in (in $\text{days}$):

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