4 girls can complete a piece of work in 8 day | vedclass

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(B) Let the total work be $W$.Efficiency of $1$ girl $= W / (4 	imes 8) = W / 32$.Efficiency of $1$ boy $= W / (3 	imes 9) = W / 27$.Efficiency of $

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(B) Let the total work be $W$.Efficiency of $1$ girl $= W / (4 	imes 8) = W / 32$.Efficiency of $1$ boy $= W / (3 	imes 9) = W / 27$.Efficiency of $1$ man $= W / (7 	imes 2) = W / 14$.Efficiency of $1$ woman $= W / (5 	imes 4) = W / 20$.Comparing the denominators: $32 > 27 > 20 > 14$.Since the numerators are the same,the efficiency is inversely proportional to the denominator.Therefore,the smallest efficiency corresponds to the largest denominator,which is $32$.Thus,girls have the minimum capacity of work.

$4$ girls can complete a piece of work in $8$ days,the same work $3$ boys can complete in $9$ days,$7$ men in $2$ days,and $5$ women in $4$ days. Who among them has the minimum capacity of work?

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