250 men can finish a work in 20 , text{days} | vedclass

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(C) The formula for work completion is $M_{1} 	imes D_{1} 	imes T_{1} = M_{2} 	imes D_{2} 	imes T_{2}$,where $M$ is the number of men,$D$ is the n

Vedclass · Accepted Answer

$313$

Vedclass · Answer

(C) The formula for work completion is $M_{1} 	imes D_{1} 	imes T_{1} = M_{2} 	imes D_{2} 	imes T_{2}$,where $M$ is the number of men,$D$ is the number of days,and $T$ is the time in hours per day.Given:$M_{1} = 250$,$D_{1} = 20$,$T_{1} = 5$$D_{2} = 10$,$T_{2} = 8$Substituting the values:$250 	imes 20 	imes 5 = M_{2} 	imes 10 	imes 8$$25000 = M_{2} 	imes 80$$M_{2} = \frac{25000}{80} = 312.5$Since the number of men must be a whole number,we round up to the next integer to ensure the work is completed within the given time.Therefore,the minimum number of men required is $313$.

$250$ men can finish a work in $20 \, \text{days}$ working $5 \, \text{hours}$ a day. To finish the work within $10 \, \text{days}$ working $8 \, \text{hours}$ a day,the minimum number of men required is:

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