$25 \%$ of $48 + 50 \%$ of $120 = ? \%$ of $1200$

$\frac{1}{4}$ of a number subtracted from $\frac{1}{3}$ of the same number gives $12$. The number is:

$\frac{(0.6^{3}-0.1^{3}-0.4^{3}-3 \times 0.6 \times 0.1 \times 0.4)}{(0.6^{2}+0.1^{2}+0.4^{2}+0.6 \times 0.1+0.6 \times 0.4-0.1 \times 0.4)}$

In a division sum,the divisor is $4$ times the quotient and twice the remainder. If $a$ and $b$ are respectively the divisor and the dividend,then

When a certain number is multiplied by $7$,the product consists entirely of fives; find the least value of such a number.

If the sum of two numbers is $22$ and the sum of their squares is $404,$ then the product of the numbers is