$8000 \div 16 - 200 = ? \times 6$

$(0.25)^{6} \div (0.125)^{2} \times (0.5)^{4} = (0.5)^{?+3}$

The product of two natural numbers is $17$. Then the sum of the reciprocals of their squares is

$140 \%$ of $56 + 56 \%$ of $140 = ?$

$A$ number when divided by $44$, gives $432$ as quotient and $0$ as remainder. What will be the remainder when dividing the same number by $31$?

What least number must be added to $7231$ so that the resulting number is exactly divisible by $5$ and $9$ together?