(21.98)^{2} - (25.02)^{2} + (13.03)^{2} = ? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To solve this,we approximate the given values to the nearest integers:$21.98 \approx 22$$25.02 \approx 25$$13.03 \approx 13$Now,substitute these v

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) To solve this,we approximate the given values to the nearest integers:$21.98 \approx 22$$25.02 \approx 25$$13.03 \approx 13$Now,substitute these values into the expression:$(22)^{2} - (25)^{2} + (13)^{2}$$= 484 - 625 + 169$$= (484 + 169) - 625$$= 653 - 625$$= 28$The value $28$ is closest to $25$ among the given options.

$(21.98)^{2} - (25.02)^{2} + (13.03)^{2} = ?$

Similar Questions

$\frac{6}{5}$ of $\frac{3}{4}$ of $\frac{1}{2}$ of $? = 3600$

Divide $50$ into two parts so that the sum of their reciprocals is $1/12$.

$4 \frac{4}{5} \div 6 \frac{2}{5} = ?$

Find the number which when multiplied by $15$ is increased by $196$.

What least number must be added to $7231$ so that the resulting number is exactly divisible by $5$ and $9$ together?

Vedclass Test Series

Exam Paper Generator

Online Exam Module