$\frac{1}{16}$ of $8432 + 50 \%$ of $? = 4429$

$18.5 \%$ of $220 + 12.4 \%$ of $680 = ?$

$A$ number is greater than $58$ times its reciprocal by $\frac{3}{4}$. What is the number?

$\frac{(0.188+0.077)^{2}+(0.188-0.077)^{2}}{0.188 \times 0.188+0.077 \times 0.077} = ?$

$\frac{(0.6^{3}-0.1^{3}-0.4^{3}-3 \times 0.6 \times 0.1 \times 0.4)}{(0.6^{2}+0.1^{2}+0.4^{2}+0.6 \times 0.1+0.6 \times 0.4-0.1 \times 0.4)}$

If the two digits of the age of Mr. Manoj are reversed,then the new age so obtained is the age of his wife. $\frac{1}{11}$ of the sum of their ages is equal to the difference between their ages. If Mr. Manoj is older than his wife,then find the difference between their ages.