(0.83 times 0.83 times 0.83 + 0.17 times 0.17 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $a = 0.83$ and $b = 0.17$.The expression is $a^3 + b^3$.We know that $a + b = 0.83 + 0.17 = 1$.Using the identity $a^3 + b^3 = (a + b)(a^2 - a

Vedclass · Accepted Answer

$1 - 0.51 	imes 0.83$

Vedclass · Answer

(B) Let $a = 0.83$ and $b = 0.17$.The expression is $a^3 + b^3$.We know that $a + b = 0.83 + 0.17 = 1$.Using the identity $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$:Since $a + b = 1$,we have $a^3 + b^3 = a^2 - ab + b^2$.Also,$(a + b)^2 = a^2 + 2ab + b^2 = 1^2 = 1$.Therefore,$a^2 + b^2 = 1 - 2ab$.Substituting this into the expression: $a^3 + b^3 = (1 - 2ab) - ab = 1 - 3ab$.Now,calculate $3ab = 3 	imes 0.83 	imes 0.17 = 0.83 	imes 0.51$.Thus,the expression equals $1 - 0.51 	imes 0.83$.

$(0.83 \times 0.83 \times 0.83 + 0.17 \times 0.17 \times 0.17)$ is equal to ...........

Similar Questions

Which fraction among $\frac{3}{7}, \frac{5}{11}$,and $\frac{6}{13}$ is the largest?

The sum of three numbers is $264$. If the first number is twice the second and the third number is one-third of the first,then the second number is:

$\frac{3}{11} \text{ of } \frac{5}{7} \text{ of } (?) = 63$

$\frac{28 \times 36}{18 \% \text{ of } 50} = ?$

Two numbers,when divided by a certain divisor,leave remainders $43$ and $37$ respectively. When their sum is divided by the same divisor,the remainder is $13$. Find the divisor.

Vedclass Test Series

Exam Paper Generator

Online Exam Module