6 - left[ frac{5}{6} + left{ 3 frac{7}{8} - 2 | vedclass

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(D) First,convert the mixed fractions into improper fractions:$3 \frac{7}{8} = \frac{31}{8}$,$2 \frac{1}{3} = \frac{7}{3}$,$1 \frac{7}{9} = \frac{16}{

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) First,convert the mixed fractions into improper fractions:$3 \frac{7}{8} = \frac{31}{8}$,$2 \frac{1}{3} = \frac{7}{3}$,$1 \frac{7}{9} = \frac{16}{9}$.Now,solve the expression inside the curly brackets:$\frac{31}{8} - \frac{7}{3} + \frac{16}{9} = \frac{279 - 168 + 128}{72} = \frac{239}{72}$.Next,add the fraction outside the curly brackets but inside the square brackets:$\frac{5}{6} + \frac{239}{72} = \frac{60 + 239}{72} = \frac{299}{72}$.Finally,subtract this from $6$:$6 - \frac{299}{72} = \frac{432 - 299}{72} = \frac{133}{72} = 1 \frac{61}{72}$.Since $1 \frac{61}{72}$ is not among the options,the correct answer is $D$.

$6 - \left[ \frac{5}{6} + \left\{ 3 \frac{7}{8} - 2 \frac{1}{3} + 1 \frac{7}{9} \right\} \right] = ?$

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