(13.95)^{2} - (15.04)^{2} + (18.08)^{2} - 32. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To solve the expression $(13.95)^{2} - (15.04)^{2} + (18.08)^{2} - 32.64$,we can approximate the values to the nearest integers:$13.95 \approx 14$

Vedclass · Accepted Answer

$260$

Vedclass · Answer

(A) To solve the expression $(13.95)^{2} - (15.04)^{2} + (18.08)^{2} - 32.64$,we can approximate the values to the nearest integers:$13.95 \approx 14$$15.04 \approx 15$$18.08 \approx 18$$32.64 \approx 33$Substituting these values into the expression:$(14)^{2} - (15)^{2} + (18)^{2} - 33$$= 196 - 225 + 324 - 33$$= (196 + 324) - (225 + 33)$$= 520 - 258$$= 262$Comparing this result with the given options,the closest value is $260$.

$(13.95)^{2} - (15.04)^{2} + (18.08)^{2} - 32.64 = ?$

Similar Questions

Three times the first of three consecutive odd integers is $3$ more than twice the third. The third integer is

$\frac{753 \times 753 + 247 \times 247 - 753 \times 247}{753 \times 753 \times 753 + 247 \times 247 \times 247} = ?$

If the sum of a number and its square is $182$,what is the number?

$69.69 - 51.54 + 73.64 = ? + 32.42$

The least value to be given to $$ so that the number $53457$ is divisible by $11$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module