1+frac{1}{2}+frac{1}{4}+frac{1}{7}+frac{1}{14 | vedclass

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(A) To solve the expression $1+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28}$,we first find the least common multiple $(LCM)$ of the d

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$2$

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(A) To solve the expression $1+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28}$,we first find the least common multiple $(LCM)$ of the denominators $2, 4, 7, 14, 28$.The $LCM$ of $2, 4, 7, 14, 28$ is $28$.Now,rewrite each fraction with the denominator $28$:$1 = \frac{28}{28}$$\frac{1}{2} = \frac{14}{28}$$\frac{1}{4} = \frac{7}{28}$$\frac{1}{7} = \frac{4}{28}$$\frac{1}{14} = \frac{2}{28}$$\frac{1}{28} = \frac{1}{28}$Adding these fractions together:$\frac{28+14+7+4+2+1}{28} = \frac{56}{28} = 2$.

$1+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28}$ is equal to

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