108 div ? of frac{1}{3} + frac{2}{5} times 3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the missing number be $x$.The given equation is: $108 \div (x 	ext{ of } \frac{1}{3}) + \frac{2}{5} 	imes 3 \frac{3}{4} = 10 \frac{1}{2}$.Fi

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(D) Let the missing number be $x$.The given equation is: $108 \div (x 	ext{ of } \frac{1}{3}) + \frac{2}{5} 	imes 3 \frac{3}{4} = 10 \frac{1}{2}$.First,convert the mixed fractions to improper fractions: $3 \frac{3}{4} = \frac{15}{4}$ and $10 \frac{1}{2} = \frac{21}{2}$.The equation becomes: $108 \div (x 	imes \frac{1}{3}) + \frac{2}{5} 	imes \frac{15}{4} = \frac{21}{2}$.Simplify the multiplication term: $\frac{2}{5} 	imes \frac{15}{4} = \frac{1}{1} 	imes \frac{3}{2} = \frac{3}{2}$.Now the equation is: $108 \div \frac{x}{3} + \frac{3}{2} = \frac{21}{2}$.Convert division to multiplication by the reciprocal: $108 	imes \frac{3}{x} + \frac{3}{2} = \frac{21}{2}$.Subtract $\frac{3}{2}$ from both sides: $\frac{324}{x} = \frac{21}{2} - \frac{3}{2} = \frac{18}{2} = 9$.Solve for $x$: $9x = 324$,so $x = \frac{324}{9} = 36$.

$108 \div ?$ of $\frac{1}{3} + \frac{2}{5} \times 3 \frac{3}{4} = 10 \frac{1}{2}$

Similar Questions

What approximate value will come in the place of the question mark $(?)$ in the following question? (You are not expected to calculate the exact value.)
$(32.13)^{2} + (23.96)^{2} - (17.11)^{2} = ?$

The value of $3+\frac{1}{\sqrt{3}}+\frac{1}{3+\sqrt{3}}+\frac{1}{\sqrt{3}-3}$ is

$13 \frac{4}{?} + 5 \frac{3}{4} \text{ of } 3 \frac{1}{5} \div 4 \frac{3}{5} = 17 \frac{4}{5}$

$(1.06+0.04)^{2}-?=4 \times 1.06 \times 0.04$

$\frac{6^{2}+7^{2}+8^{2}+9^{2}+10^{2}}{\sqrt{7+4 \sqrt{3}}-\sqrt{4+2 \sqrt{3}}}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module