sqrt{? times 7} times 18 = 84 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the missing value be $x$.$\sqrt{x 	imes 7} 	imes 18 = 84$Divide both sides by $18$:$\sqrt{x 	imes 7} = \frac{84}{18} = \frac{14}{3}$Square

Vedclass · Accepted Answer

$3.11$

Vedclass · Answer

(A) Let the missing value be $x$.$\sqrt{x 	imes 7} 	imes 18 = 84$Divide both sides by $18$:$\sqrt{x 	imes 7} = \frac{84}{18} = \frac{14}{3}$Square both sides to remove the square root:$x 	imes 7 = \left(\frac{14}{3}ight)^2$$x 	imes 7 = \frac{196}{9}$Solve for $x$:$x = \frac{196}{9 	imes 7}$$x = \frac{196}{63}$$x = \frac{28}{9} \approx 3.111...$Rounding to two decimal places,we get $x = 3.11$.

$\sqrt{? \times 7} \times 18 = 84$

Similar Questions

Find the value of $\frac{(0.064-0.008)(0.16-0.04)}{(0.16+0.08+0.04)(0.4+0.2)^{3}}$.

The value of $3+\frac{3}{3+\frac{1}{3+\frac{1}{3}}}$ is:

If $x + \frac{1}{x} = \sqrt{13}$,then $\frac{3x}{x^2 - 1}$ is equal to:

What is the difference between the biggest and the smallest fraction among $\frac{2}{3}, \frac{3}{4}, \frac{4}{5}$ and $\frac{5}{6}$?

What should come in place of the question mark $(?)$ in the following equation?
$30.01^{2} - 19.98^{2} - ? = 21.81^{2}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module