11111_{2} - 10001_{2} = ? | vedclass

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Question

(C) To subtract $10001_{2}$ from $11111_{2}$,we perform binary subtraction:$11111_{2} = 16 + 8 + 4 + 2 + 1 = 31_{10}$$10001_{2} = 16 + 0 + 0 + 0 + 1 =

Vedclass · Accepted Answer

$1110_{2}$

Vedclass · Answer

(C) To subtract $10001_{2}$ from $11111_{2}$,we perform binary subtraction:$11111_{2} = 16 + 8 + 4 + 2 + 1 = 31_{10}$$10001_{2} = 16 + 0 + 0 + 0 + 1 = 17_{10}$Subtracting the decimal values:$31 - 17 = 14_{10}$Now,convert $14_{10}$ back to binary:$14 \div 2 = 7$ remainder $0$$7 \div 2 = 3$ remainder $1$$3 \div 2 = 1$ remainder $1$$1 \div 2 = 0$ remainder $1$Reading remainders from bottom to top,we get $1110_{2}$.Alternatively,using direct binary subtraction:$\begin{array}{r} 11111 \ -10001 \ \hline 01110 \end{array}$Thus,$11111_{2} - 10001_{2} = 1110_{2}$.

$11111_{2} - 10001_{2} = ?$

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