sqrt{frac{4}{3}}-sqrt{frac{3}{4}}=? | vedclass

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Question

(A) To solve the expression $\sqrt{\frac{4}{3}}-\sqrt{\frac{3}{4}}$,we first simplify the square roots of the individual terms.$\sqrt{\frac{4}{3}} = \

Vedclass · Accepted Answer

$\frac{1}{2 \sqrt{3}}$

Vedclass · Answer

(A) To solve the expression $\sqrt{\frac{4}{3}}-\sqrt{\frac{3}{4}}$,we first simplify the square roots of the individual terms.$\sqrt{\frac{4}{3}} = \frac{\sqrt{4}}{\sqrt{3}} = \frac{2}{\sqrt{3}}$$\sqrt{\frac{3}{4}} = \frac{\sqrt{3}}{\sqrt{4}} = \frac{\sqrt{3}}{2}$Now,subtract the two fractions:$\frac{2}{\sqrt{3}} - \frac{\sqrt{3}}{2} = \frac{2 	imes 2 - \sqrt{3} 	imes \sqrt{3}}{2 \sqrt{3}}$$= \frac{4 - 3}{2 \sqrt{3}}$$= \frac{1}{2 \sqrt{3}}$

$\sqrt{\frac{4}{3}}-\sqrt{\frac{3}{4}}=?$

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