$(x)^{3} = 729$,find the value of $x$.

$(x)^{3} = 4913$. Find the value of $x$.

The sum of the square of the first number and the cube of the second number is $568$. Also,the square of the second number is $15$ less than the square of $8$. What is the value of $\frac{3}{5}$ of the first number? (Assuming both numbers are positive)

$\sqrt[3]{4663} + 349 = ? \div 21.003$

Find the cube root of $0.000729$.

What is the smallest number by which $5600$ must be divided to make it a perfect cube?