12, 14, 32, 102, 416, 2090, ? | vedclass

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Question

(B) The pattern follows the rule: $(	ext{Term} 	imes n) + (2 	imes n)$,where $n$ is the position index starting from $1$.$12 	imes 1 + 2 	imes 1

Vedclass · Accepted Answer

$12552$

Vedclass · Answer

(B) The pattern follows the rule: $(	ext{Term} 	imes n) + (2 	imes n)$,where $n$ is the position index starting from $1$.$12 	imes 1 + 2 	imes 1 = 12 + 2 = 14$$14 	imes 2 + 2 	imes 2 = 28 + 4 = 32$$32 	imes 3 + 2 	imes 3 = 96 + 6 = 102$$102 	imes 4 + 2 	imes 4 = 408 + 8 = 416$$416 	imes 5 + 2 	imes 5 = 2080 + 10 = 2090$Following this pattern,the next term is:$2090 	imes 6 + 2 	imes 6 = 12540 + 12 = 12552$

$5$	$294$	$69$	$238$
$13$	$(a)$	$(b)$	$(c)$	$(d)$	$(e)$

$12, 14, 32, 102, 416, 2090, ?$

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