Find the missing term in the series: 625, 5, | vedclass

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Question

(C) The given series is a combination of two alternating series:$(i)$ The first series consists of terms at odd positions: $625, 125, 25, 5$. Each ter

Vedclass · Accepted Answer

$125$

Vedclass · Answer

(C) The given series is a combination of two alternating series:$(i)$ The first series consists of terms at odd positions: $625, 125, 25, 5$. Each term is obtained by dividing the previous term by $5$ $(625 \div 5 = 125, 125 \div 5 = 25, 25 \div 5 = 5)$.$(ii)$ The second series consists of terms at even positions: $5, 25, ?$. Each term is obtained by multiplying the previous term by $5$ $(5 	imes 5 = 25, 25 	imes 5 = 125)$.Therefore,the missing term is $125$.

$4$	$9$	$25$	$103$
$3$	$(a)$	$(b)$	$(c)$

Find the missing term in the series: $625, 5, 125, 25, 25, ?, 5$

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