$CH_2 = CH_2 \xrightarrow[KOH / H_2O]{KMnO_4} X$. The product $X$ in the above reaction is:

$But-1-ene$ may be converted to $butane$ by reaction with:

Addition of $HCl$ to $3,3$-dimethyl-$1$-butene yields two products,one of which has a rearranged carbon skeleton. Among the following carbocations,select the possible intermediates in that reaction:
$1.$ $(CH_3)_3C-C^+H-CH_3$
$2.$ $(CH_3)_3C-CH_2-C^+H_2$
$3.$ $(CH_3)_2C(Cl)-C^+(CH_3)_2$
$4.$ $(CH_3)_2C^+-CH(CH_3)_2$

Reaction of $Br_2$ on ethylene in the presence of $NaCl$ gives:

In the reaction sequence:
$Cyclohexane$ $\xrightarrow{hv/Cl_2} (X)$ $\xrightarrow{alc. KOH/\Delta} (Y)$ $\xrightarrow[(ii) H_2O/Zn]{(i) O_3} (Z)$
$(Z)$ will be :

Conc. $H_2SO_4$ reacts with $C_2H_5OH$ at $170\,^{\circ}C$ to form