$3$-Phenylpropene on reaction with $HBr$ gives (as a major product)
- A$C_6H_5CH_2CH(Br)CH_3$
- B$C_6H_5CH(Br)CH_2CH_3$
- C$C_6H_5CH_2CH_2CH_2Br$
- D$C_6H_5CH(Br)CH = CH_2$
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Similar Questions
Identify the correct statement for the below given transformation:
$CH_{3}CH_{2}CH_{2}CH(N^{+}(CH_{3})_{3})CH_{3}$ $\xrightarrow{C_{2}H_{5}ONa / C_{2}H_{5}OH} A (\text{major}) + B (\text{minor})$
$CH_{3}CH_{2}CH_{2}CH(N^{+}(CH_{3})_{3})CH_{3}$ $\xrightarrow{C_{2}H_{5}ONa / C_{2}H_{5}OH} A (\text{major}) + B (\text{minor})$
The correct order of rates of $C-Br$ bond ionisation of the following bromides is
The correct reactivity order for $S_N2$ reaction is:
$(i)$ $CH_3COCH_2Cl$
(ii) $CH_2=CH-CH_2Cl$
(iii) $CH_3CH_2CH_2Cl$
$(i)$ $CH_3COCH_2Cl$
(ii) $CH_2=CH-CH_2Cl$
(iii) $CH_3CH_2CH_2Cl$
Difficult
View SolutionChloropicrin is obtained by the reaction of
DifficultAIPMT 2004
View SolutionCorrect order of nucleophilicity for $S_N2$ reaction
Medium
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