$7^{5} \div 7^{3} \div 7^{2} \times 7^{4} \times \frac{1}{7^{3}} = 7^{?}$

  • A
    $1$
  • B
    $2$
  • C
    $0$
  • D
    $3$

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When $\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}\right)$ is divided by $\left(\frac{2}{5}-\frac{5}{9}+\frac{3}{5}-\frac{7}{18}\right),$ the result is:

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