(7.5 times 7.5 + 37.5 + 2.5 times 2.5) is equ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The expression is $(7.5 	imes 7.5 + 37.5 + 2.5 	imes 2.5)$.We can rewrite $37.5$ as $2 	imes 7.5 	imes 2.5$ because $2 	imes 7.5 = 15$ and $1

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(D) The expression is $(7.5 	imes 7.5 + 37.5 + 2.5 	imes 2.5)$.We can rewrite $37.5$ as $2 	imes 7.5 	imes 2.5$ because $2 	imes 7.5 = 15$ and $15 	imes 2.5 = 37.5$.Thus,the expression becomes $(7.5)^2 + 2(7.5)(2.5) + (2.5)^2$.This is in the form of the algebraic identity $a^2 + 2ab + b^2 = (a + b)^2$,where $a = 7.5$ and $b = 2.5$.Substituting the values,we get $(7.5 + 2.5)^2 = (10)^2 = 100$.

$(7.5 \times 7.5 + 37.5 + 2.5 \times 2.5)$ is equal to

Similar Questions

What is the value of $\frac{(0.5)^{3}-(0.1)^{3}}{(0.5)^{2}+0.5 \times 0.1+(0.1)^{2}}?$

The value of $999 \frac{995}{999} \times 999$ is

$\frac{4.2 \times 4.2 - 1.9 \times 1.9}{2.3 \times 6.1} = ?$

If $\frac{x-a^{2}}{b+c}+\frac{x-b^{2}}{c+a}+\frac{x-c^{2}}{a+b}=4(a+b+c),$ then $x$ is equal to:

If $x^{2}+3x+1=0,$ then the value of $x^{3}+\frac{1}{x^{3}}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module