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(C) When $3$ coins are tossed,the sample space $S$ is given by:$S = \{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT\}$Total number of outcomes $= 8$.Let $E$

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$\frac{7}{8}$

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(C) When $3$ coins are tossed,the sample space $S$ is given by:$S = \{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT\}$Total number of outcomes $= 8$.Let $E$ be the event of getting at most $2$ heads.The complement event $E'$ is getting $3$ heads.The only outcome with $3$ heads is $\{HHH\}$,so $n(E') = 1$.The probability of getting $3$ heads is $P(E') = \frac{1}{8}$.Using the complement rule,the probability of getting at most $2$ heads is:$P(E) = 1 - P(E') = 1 - \frac{1}{8} = \frac{7}{8}$.

$3$ coins are tossed. Find the probability of getting at most $2$ heads.

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